simplify \\frac{1+\\sec(t)}{1+\\cos(t)} to a single trig function.

simplify \\frac{1+\\sec(t)}{1+\\cos(t)} to a single trig function.
Answer
Explanation:
Step1: Substitute $\sec(t)=\frac{1}{\cos(t)}$
$$\frac{1+\sec(t)}{1 + \cos(t)}=\frac{1+\frac{1}{\cos(t)}}{1+\cos(t)}$$
Step2: Simplify the numerator
$$\frac{1+\frac{1}{\cos(t)}}{1+\cos(t)}=\frac{\frac{\cos(t)+ 1}{\cos(t)}}{1+\cos(t)}$$
Step3: Divide by a fraction
$$\frac{\frac{\cos(t)+1}{\cos(t)}}{1+\cos(t)}=\frac{\cos(t)+1}{\cos(t)}\cdot\frac{1}{1+\cos(t)}$$
Step4: Cancel out the common factor
$$\frac{\cos(t)+1}{\cos(t)}\cdot\frac{1}{1+\cos(t)}=\frac{1}{\cos(t)}$$
Answer:
$\sec(t)$