what is sin α?\n(-√13,6)\nr\nα\nsin α = ?
what is sin α?\n(-√13,6)\nr\nα\nsin α = ?
Answer
Explanation:
Step1: Calculate the value of ( r )
According to the formula ( r=\sqrt{x^{2}+y^{2}} ), where ( x =-\sqrt{13} ) and ( y = 6 ). [ \begin{align*} r&=\sqrt{(-\sqrt{13})^{2}+6^{2}}\ &=\sqrt{13 + 36}\ &=\sqrt{49}\ &=7 \end{align*} ]
Step2: Calculate ( \sin\alpha )
According to the definition of trigonometric functions ( \sin\alpha=\frac{y}{r} ), substitute ( y = 6 ) and ( r = 7 ) into it. [ \sin\alpha=\frac{6}{7} ]
Answer:
(\frac{6}{7})