3. sketch the graph of the equation $y=-2\\sin(\\pi(x - 1))-4$.

3. sketch the graph of the equation $y=-2\\sin(\\pi(x - 1))-4$.

3. sketch the graph of the equation $y=-2\\sin(\\pi(x - 1))-4$.

Answer

Explanation:

Step1: Identify the general form of the sine function

The general form of a sine function is (y = A\sin(B(x - C))+D). For the given function (y=-2\sin(\pi(x - 1))-4), we have (A=-2), (B = \pi), (C = 1), (D=-4).

Step2: Determine the amplitude

The amplitude is (|A|). Here, (|A|=|-2| = 2).

Step3: Calculate the period

The period of a sine function (y = A\sin(B(x - C))+D) is (T=\frac{2\pi}{|B|}). Since (B=\pi), (T=\frac{2\pi}{\pi}=2).

Step4: Find the phase - shift

The phase - shift is (C). Here, the phase - shift is (1) (to the right).

Step5: Determine the vertical - shift

The vertical - shift is (D=-4).

To sketch the graph:

  • Start with the basic sine function (y = \sin(x)) which has a period of (2\pi), amplitude (1), no phase - shift and no vertical - shift.
  • Compress the period of (y = \sin(x)) from (2\pi) to (2) (because (B=\pi)).
  • Reflect the graph about the (x) - axis (because (A=-2)).
  • Stretch the graph vertically by a factor of (2) (because (|A| = 2)).
  • Shift the graph (1) unit to the right (because (C = 1)).
  • Shift the graph (4) units down (because (D=-4)).

Answer:

The graph of (y=-2\sin(\pi(x - 1))-4) has amplitude (2), period (2), phase - shift (1) unit to the right and vertical - shift (4) units down.