solve the equation for all exact solutions where appropriate\nround approximate answers in degrees to the…

solve the equation for all exact solutions where appropriate\nround approximate answers in degrees to the nearest tenth\nwrite answers using the least possible nonnegative angle\nmeasures\n\n\\( \\sin \\theta \\sec \\theta - \\sin \\theta = 0 \\)\n\nchoose the correct answer below\n\n\\( \\bigcirc \\) a. \\( \\{ 0 ^ { \\circ } \\} \\)\n\\( \\bigcirc \\) b. \\( \\{ 90 ^ { \\circ } n \\), where \\( n \\) is any integer \\}\n\\( \\bigcirc \\) c. \\( \\{ 270 ^ { \\circ } n \\), where \\( n \\) is any integer \\}\n\\( \\bigcirc \\) d. \\( \\{ 180 ^ { \\circ } n \\), where \\( n \\) is any integer \\}

solve the equation for all exact solutions where appropriate\nround approximate answers in degrees to the nearest tenth\nwrite answers using the least possible nonnegative angle\nmeasures\n\n\\( \\sin \\theta \\sec \\theta - \\sin \\theta = 0 \\)\n\nchoose the correct answer below\n\n\\( \\bigcirc \\) a. \\( \\{ 0 ^ { \\circ } \\} \\)\n\\( \\bigcirc \\) b. \\( \\{ 90 ^ { \\circ } n \\), where \\( n \\) is any integer \\}\n\\( \\bigcirc \\) c. \\( \\{ 270 ^ { \\circ } n \\), where \\( n \\) is any integer \\}\n\\( \\bigcirc \\) d. \\( \\{ 180 ^ { \\circ } n \\), where \\( n \\) is any integer \\}

Answer

Explanation:

Step1: Simplify the equation

Use the identity (\sec\theta=\frac{1}{\cos\theta}). The given equation (\sin\theta\sec\theta - \sin\theta = 0) becomes (\sin\theta\frac{1}{\cos\theta}-\sin\theta = 0). Factor out (\sin\theta): (\sin\theta(\frac{1}{\cos\theta}- 1)=0).

Step2: Set each factor equal to zero

Case 1: (\sin\theta = 0). The general solution for (\sin\theta=0) is (\theta = 180^{\circ}n), where (n\in\mathbb{Z}) (using the unit - circle, (\sin\theta = y) - coordinate on the unit circle, and (y = 0) when (\theta=0^{\circ},180^{\circ},360^{\circ},\cdots)). Case 2: (\frac{1}{\cos\theta}-1 = 0). (\frac{1}{\cos\theta}=1), then (\cos\theta = 1). The general solution for (\cos\theta = 1) is also (\theta = 360^{\circ}n=180^{\circ}(2n)) ((n\in\mathbb{Z})).

Answer:

D. ({180^{\circ}n,\text{ where }n\text{ is any integer}})