solve the logarithmic equation for x. if there are no answers, enter null. round your answer to two decimal…

solve the logarithmic equation for x. if there are no answers, enter null. round your answer to two decimal places, if necessary. log(x + 1) - log(x + 2) = log(1/x)

solve the logarithmic equation for x. if there are no answers, enter null. round your answer to two decimal places, if necessary. log(x + 1) - log(x + 2) = log(1/x)

Answer

Explanation:

Step1: Apply log quotient rule

Using (\log a - \log b=\log\frac{a}{b}), rewrite left side: (\log\left(\frac{x + 1}{x + 2}\right)=\log\left(\frac{1}{x}\right))

Step2: Remove logs (since (\log a=\log b\Rightarrow a = b))

Set (\frac{x + 1}{x + 2}=\frac{1}{x}), cross - multiply: (x(x + 1)=x + 2)

Step3: Expand and simplify

Expand left side: (x^{2}+x=x + 2), subtract (x + 2) from both sides: (x^{2}-2 = 0)

Step4: Solve quadratic equation

(x^{2}=2), so (x=\pm\sqrt{2}). But for (\log(x + 1)), (\log(x + 2)), (\log\left(\frac{1}{x}\right)) to be defined:

  • (x+1>0\Rightarrow x>- 1)
  • (x + 2>0\Rightarrow x>-2)
  • (\frac{1}{x}>0\Rightarrow x>0)

So (x=\sqrt{2}\approx1.41) (reject (x =-\sqrt{2}) as it doesn't satisfy (x>0))

Answer:

(1.41)