step 1\nif two numbers have a difference of 198, and one of them is x + 198, then the other is +396…

step 1\nif two numbers have a difference of 198, and one of them is x + 198, then the other is +396 x\n\nstep 2\nthe product of two numbers x and x + 198 can be simplified to be x² + 198 x.\n\nstep 3\nif f(x) = x² + 198x, then f(x) = 2x + 198.\n\nstep 4\nto minimize the product f(x) = x² + 198x, we must solve 0 = f(x) = 2x + 198, which means x =

step 1\nif two numbers have a difference of 198, and one of them is x + 198, then the other is +396 x\n\nstep 2\nthe product of two numbers x and x + 198 can be simplified to be x² + 198 x.\n\nstep 3\nif f(x) = x² + 198x, then f(x) = 2x + 198.\n\nstep 4\nto minimize the product f(x) = x² + 198x, we must solve 0 = f(x) = 2x + 198, which means x =

Answer

Explanation:

Step1: Solve the equation

We have the equation (0 = 2x+198). Subtract (198) from both sides: (2x=- 198).

Step2: Find the value of (x)

Divide both sides by (2): (x=\frac{-198}{2}=-99).

Answer:

(-99)