step 2 we can solve for the limit as follows. (if the quantity diverges, enter diverges.) lim n→∞ 8 - 1/n 7…

step 2 we can solve for the limit as follows. (if the quantity diverges, enter diverges.) lim n→∞ 8 - 1/n 7 + 1/n =

step 2 we can solve for the limit as follows. (if the quantity diverges, enter diverges.) lim n→∞ 8 - 1/n 7 + 1/n =

Answer

Answer:

$\frac{8}{7}$

Explanation:

Step1: Analyze the limit of $\frac{1}{n}$ as $n\to\infty$

As $n\to\infty$, $\lim_{n\rightarrow\infty}\frac{1}{n}=0$.

Step2: Substitute the limit value

$\lim_{n\rightarrow\infty}\frac{8 - \frac{1}{n}}{7+\frac{1}{n}}=\frac{\lim_{n\rightarrow\infty}(8 - \frac{1}{n})}{\lim_{n\rightarrow\infty}(7+\frac{1}{n})}=\frac{8 - 0}{7+0}=\frac{8}{7}$