tammy is driving a racecar. the table below gives the distance d(t) (in met\n\n| time t (seconds) | distance…

tammy is driving a racecar. the table below gives the distance d(t) (in met\n\n| time t (seconds) | distance d(t) (meters) |\n| ---- | ---- |\n| 0 | 0 |\n| 2 | 71.2 |\n| 4 | 166.4 |\n| 6 | 172.8 |\n| 10 | 239.6 |\n\n(a) find the average rate of change for the distance driven from 0 seconds to 2 seconds.\n\n meters per second\n\n(b) find the average rate of change for the distance driven from 6 seconds to 10 seconds.\n\n meters per second
Answer
Explanation:
Step1: Recall average - rate - of - change formula
The average rate of change of a function $y = f(x)$ from $x = a$ to $x = b$ is $\frac{f(b)-f(a)}{b - a}$. For the distance function $D(t)$, the average rate of change from $t=a$ to $t = b$ is $\frac{D(b)-D(a)}{b - a}$.
Step2: Calculate average rate of change for part (a)
Here, $a = 0$, $b = 2$, $D(0)=0$, and $D(2)=71.2$. Substitute into the formula: $\frac{D(2)-D(0)}{2 - 0}=\frac{71.2-0}{2}=\frac{71.2}{2}=35.6$.
Step3: Calculate average rate of change for part (b)
Here, $a = 6$, $b = 10$, $D(6)=172.8$, and $D(10)=239.6$. Substitute into the formula: $\frac{D(10)-D(6)}{10 - 6}=\frac{239.6 - 172.8}{4}=\frac{66.8}{4}=16.7$.
Answer:
(a) 35.6 (b) 16.7