what does the transformation f(x) → f(1/8x) do to the graph of f(x)? shrinks it horizontally stretches it…

Explanation:

Step1: Recall horizontal - stretch/shrink rule

For a function $y = f(x)$ and a transformation $y=f(bx)$, if $|b|> 1$, the graph is shrunk horizontally by a factor of $\frac{1}{|b|}$, and if $0<|b|<1$, the graph is stretched horizontally by a factor of $\frac{1}{|b|}$. In the transformation $f(x)\to f(\frac{1}{8}x)$, we have $b = \frac{1}{8}$, and since $0<\frac{1}{8}<1$.

Step2: Determine the transformation type

The graph of $y = f(x)$ is stretched horizontally by a factor of $\frac{1}{\frac{1}{8}}=8$.

Answer:

stretches it horizontally