use the graph to determine\na. open intervals on which the function is increasing, if any\nb. open intervals…

use the graph to determine\na. open intervals on which the function is increasing, if any\nb. open intervals on which the function is decreasing, if any\nc. open intervals on which the function is constant, if any\nb. select the correct choice below and, if necessary, fill in the answer box to complete your choice\na the function is decreasing on the interval(s)\n(type your answer in interval notation. use a comma to separate answers as needed)\nb there is no interval on which the function is decreasing

use the graph to determine\na. open intervals on which the function is increasing, if any\nb. open intervals on which the function is decreasing, if any\nc. open intervals on which the function is constant, if any\nb. select the correct choice below and, if necessary, fill in the answer box to complete your choice\na the function is decreasing on the interval(s)\n(type your answer in interval notation. use a comma to separate answers as needed)\nb there is no interval on which the function is decreasing

Answer

Explanation:

Step 1: Analyze the function's behavior

A function is increasing if, as (x) increases, (y) increases. A function is decreasing if, as (x) increases, (y) decreases. A function is constant if, as (x) increases, (y) remains the same.

Step 2: Check for increasing intervals

Looking at the graph, there is no interval where the function is increasing.

Step 3: Check for decreasing intervals

For the part of the graph from (x =-\infty) to (x = 1), as (x) increases, (y) decreases. In interval notation, this is ((-\infty,1))

Step 4: Check for constant intervals

For the part of the graph from (x = 1) to (x=\infty), as (x) increases, (y) remains the same (equal to (2)). In interval notation, this is ((1,\infty))

Answer:

a. There is no interval on which the function is increasing. b. The function is decreasing on the interval ((-\infty,1)) c. The function is constant on the interval ((1,\infty))