use the graph of the function f shown to the right to estimate the indicated function values and limits…

use the graph of the function f shown to the right to estimate the indicated function values and limits. complete parts (a) through (e). (a) find the value of \\(\\lim_{x\\to - 2^{-}}f(x)\\). select the correct choice below and, if necessary, fill in the answer box to complete your choice. a. \\(\\lim_{x\\to - 2^{-}}f(x)=\\square\\) b. the limit does not exist. (b) find the value of \\(\\lim_{x\\to - 2^{+}}f(x)\\). select the correct choice below and, if necessary, fill in the answer box to complete your choice. a. \\(\\lim_{x\\to - 2^{+}}f(x)=\\square\\) b. the limit does not exist. (c) find the value of \\(\\lim_{x\\to - 2}f(x)\\). select the correct choice below and, if necessary, fill in the answer box to complete your choice.
Answer
Explanation:
Step1: Analyze left - hand limit
To find $\lim_{x\rightarrow - 2^{-}}f(x)$, we look at the behavior of the function $f(x)$ as $x$ approaches $-2$ from the left - hand side (values of $x$ less than $-2$ getting closer to $-2$). By observing the graph, we determine the $y$ - value the function approaches.
Step2: Analyze right - hand limit
To find $\lim_{x\rightarrow - 2^{+}}f(x)$, we look at the behavior of the function $f(x)$ as $x$ approaches $-2$ from the right - hand side (values of $x$ greater than $-2$ getting closer to $-2$). By observing the graph, we determine the $y$ - value the function approaches.
Step3: Determine overall limit
The limit $\lim_{x\rightarrow - 2}f(x)$ exists if and only if $\lim_{x\rightarrow - 2^{-}}f(x)=\lim_{x\rightarrow - 2^{+}}f(x)$. If they are equal, that common value is $\lim_{x\rightarrow - 2}f(x)$. If they are not equal, the limit does not exist.
Since we don't have the actual graph to provide numerical values: (A) Without seeing the graph, we can't give a numerical answer. But the process is to look at the $y$ - value as $x$ approaches $-2$ from the left. (B) Without seeing the graph, we can't give a numerical answer. But the process is to look at the $y$ - value as $x$ approaches $-2$ from the right. (C) If $\lim_{x\rightarrow - 2^{-}}f(x)=\lim_{x\rightarrow - 2^{+}}f(x)=L$, then $\lim_{x\rightarrow - 2}f(x)=L$. If $\lim_{x\rightarrow - 2^{-}}f(x)\neq\lim_{x\rightarrow - 2^{+}}f(x)$, then $\lim_{x\rightarrow - 2}f(x)$ does not exist.
Since we need to answer based on a non - provided graph, we can't give specific final answers. But the general approach is as above. If we assume we had a graph and found: Let's say from the graph $\lim_{x\rightarrow - 2^{-}}f(x) = 3$, $\lim_{x\rightarrow - 2^{+}}f(x)=3$
Answer:
(A) A. $\lim_{x\rightarrow - 2^{-}}f(x)=3$ (B) A. $\lim_{x\rightarrow - 2^{+}}f(x)=3$ (C) A. $\lim_{x\rightarrow - 2}f(x)=3$
(The above numerical values are just for illustration purposes. The actual values should be determined from the given graph.)