use identities to find values of the sine and cosine functions for the angle measure. \nθ, given that ( cos…

use identities to find values of the sine and cosine functions for the angle measure. \nθ, given that ( cos 2\theta=\frac{56}{65} ) and ( 90^{circ}<\theta<180^{circ} )\n( sin \theta=square )\n(simplify your answer, including any radicals. use integers or fractions for any numbers in the expression. rationalize all denominators.)
Answer
Explanation:
Step1: Use the double - angle identity for cosine
The double - angle identity for cosine is (\cos2\theta = 1 - 2\sin^{2}\theta). Given (\cos2\theta=\frac{56}{65}), we substitute it into the identity: (\frac{56}{65}=1 - 2\sin^{2}\theta)
Step2: Solve for (\sin^{2}\theta)
First, rearrange the equation: (2\sin^{2}\theta=1-\frac{56}{65}) (2\sin^{2}\theta=\frac{65 - 56}{65}=\frac{9}{65}) Then (\sin^{2}\theta=\frac{9}{130})
Step3: Determine the sign of (\sin\theta)
Since (90^{\circ}<\theta<180^{\circ}), (\theta) is in the second quadrant. In the second quadrant, (\sin\theta> 0) So (\sin\theta=\sqrt{\frac{9}{130}}=\frac{3}{\sqrt{130}}=\frac{3\sqrt{130}}{130})
Answer:
(\frac{3\sqrt{130}}{130})