use the intermediate value theorem to show that the p(x) = 4x^2 + x - 5; -2 and -1 p(-2) = p(-1) = because…

use the intermediate value theorem to show that the p(x) = 4x^2 + x - 5; -2 and -1 p(-2) = p(-1) = because the signs of the results are oppo need help? read it watch it submit answer 5.55/5.55 points details my notes previous answers ask your teacher use the intermediate value theorem to show that

use the intermediate value theorem to show that the p(x) = 4x^2 + x - 5; -2 and -1 p(-2) = p(-1) = because the signs of the results are oppo need help? read it watch it submit answer 5.55/5.55 points details my notes previous answers ask your teacher use the intermediate value theorem to show that

Answer

Explanation:

Step1: Calculate $P(-2)$

Substitute $x = - 2$ into $P(x)=4x^{2}+x - 5$. $P(-2)=4\times(-2)^{2}+(-2)-5=4\times4 - 2 - 5=16-2 - 5=9$

Step2: Calculate $P(-1)$

Substitute $x=-1$ into $P(x)=4x^{2}+x - 5$. $P(-1)=4\times(-1)^{2}+(-1)-5=4\times1-1 - 5=4 - 1 - 5=-2$

Answer:

$P(-2)=9$ $P(-1)=-2$