use linear approximation, i.e. the tangent line, to approximate $\frac{1}{0.502}$ as follows: let…
use linear approximation, i.e. the tangent line, to approximate $\frac{1}{0.502}$ as follows: let $f(x)=\frac{1}{x}$ and find the equation of the tangent line to $f(x)$ at a \nice\ point near $0.502$. then use this to approximate $\frac{1}{0.502}$.