use part one of the fundamental theorem of calculus to find the derivative of the function. g(s) = ∫₅ˢ (t…

use part one of the fundamental theorem of calculus to find the derivative of the function. g(s) = ∫₅ˢ (t - t⁵)² dt g(s) =

use part one of the fundamental theorem of calculus to find the derivative of the function. g(s) = ∫₅ˢ (t - t⁵)² dt g(s) =

Answer

Answer:

$(s - s^{5})^{2}$

Explanation:

Step1: Aplicar el primer teorema fundamental del cálculo

Según el primer teorema fundamental del cálculo, si $g(s)=\int_{a}^{s}f(t)dt$, entonces $g^{\prime}(s) = f(s)$.

Step2: Identificar la función $f(t)$

En $g(s)=\int_{5}^{s}(t - t^{5})^{2}dt$, la función $f(t)=(t - t^{5})^{2}$.

Step3: Obtener la derivada

Sustituyendo $t$ por $s$ en $f(t)$, se tiene $g^{\prime}(s)=(s - s^{5})^{2}$.