using a quadratic equation to solve an area problem\na rectangular piece of paper has a width that is 3…

using a quadratic equation to solve an area problem\na rectangular piece of paper has a width that is 3 inches less than its length. it is cut in half along a diagonal to create two congruent right triangles with areas of 44 square inches. which statements are true? check all that apply.\n- the area of the rectangle is 88 square inches.\n- the equation ( x(x - 3) = 44 ) can be used to solve for the dimensions of the triangle.\n- the equation ( x^2 - 3x - 88 = 0 ) can be used to solve for the length of the rectangle.\n- the triangle has a base of 11 inches and a height of 8 inches.\n- the rectangle has a width of 4 inches.

using a quadratic equation to solve an area problem\na rectangular piece of paper has a width that is 3 inches less than its length. it is cut in half along a diagonal to create two congruent right triangles with areas of 44 square inches. which statements are true? check all that apply.\n- the area of the rectangle is 88 square inches.\n- the equation ( x(x - 3) = 44 ) can be used to solve for the dimensions of the triangle.\n- the equation ( x^2 - 3x - 88 = 0 ) can be used to solve for the length of the rectangle.\n- the triangle has a base of 11 inches and a height of 8 inches.\n- the rectangle has a width of 4 inches.

Answer

Answer:

The area of the rectangle is 88 square inches. The equation (x^{2}-3x - 88=0) can be used to solve for the length of the rectangle. The triangle has a base of 11 inches and a height of 8 inches. The rectangle has a width of 8 inches.