what is the value of $arccos(sin(\frac{pi}{2}))$?\n0\n1\n$pi$\n$2pi$

Answer:

A. 0

Explanation:

Step1: Calculate $\sin(\frac{\pi}{2})$

We know that $\sin(\frac{\pi}{2}) = 1$.

Step2: Calculate $\arccos(1)$

The range of the inverse - cosine function $y = \arccos(x)$ is $[0,\pi]$. And $\arccos(1)=0$ since $\cos(0) = 1$.