if $f(x) = 1 - x$, which value is equivalent to $|f(i)|$?\n○ 0\n○ 1\n○ $sqrt{2}$\n○ $sqrt{-1}$

if $f(x) = 1 - x$, which value is equivalent to $|f(i)|$?\n○ 0\n○ 1\n○ $sqrt{2}$\n○ $sqrt{-1}$

if $f(x) = 1 - x$, which value is equivalent to $|f(i)|$?\n○ 0\n○ 1\n○ $sqrt{2}$\n○ $sqrt{-1}$

Answer

Explanation:

Step1: Find f(i)

Substitute ( x = i ) into ( f(x)=1 - x ). So ( f(i)=1 - i ).

Step2: Find ( |f(i)| )

The modulus of a complex number ( a+bi ) is ( \sqrt{a^{2}+b^{2}} ). Here, for ( 1 - i ) (where ( a = 1 ), ( b=- 1 )), ( |f(i)|=\sqrt{1^{2}+(-1)^{2}}=\sqrt{1 + 1}=\sqrt{2} ).

Answer:

(\sqrt{2})