what is the value of $x$ in the expression $log_{2}(3x + 8) = 5$?\n$x = \\square$

Explanation:

Step1: Convert log to exponential form

If $\log_b(a)=c$, then $b^c=a$. So: $$2^5 = 3x + 8$$

Step2: Calculate $2^5$

Compute the power: $$32 = 3x + 8$$

Step3: Isolate the term with $x$

Subtract 8 from both sides: $$32 - 8 = 3x$$ $$24 = 3x$$

Step4: Solve for $x$

Divide both sides by 3: $$x = \frac{24}{3}$$

Answer:

$x=8$