what is the value of x in x = sin^(-1)(-1/2)? -2π/3 -π/6 2π/3 7π/6
what is the value of x in x = sin^(-1)(-1/2)? -2π/3 -π/6 2π/3 7π/6
Answer
Explanation:
Step1: Recall inverse - sine range
The range of (y = \sin^{-1}(x)) is (\left[-\frac{\pi}{2},\frac{\pi}{2}\right]).
Step2: Find the angle
We know that (\sin\left(-\frac{\pi}{6}\right)=-\frac{1}{2}) and (-\frac{\pi}{6}\in\left[-\frac{\pi}{2},\frac{\pi}{2}\right]).
Answer:
B. (-\frac{\pi}{6})