where are the vertical asymptotes of y = tan x between -π and π? -\\frac{π}{?} and \\frac{π}{?}

Explanation:

Step1: Recall tangent function formula

$\tan x=\frac{\sin x}{\cos x}$. Vertical asymptotes occur where $\cos x = 0$.

Step2: Solve $\cos x = 0$ in given interval

In the interval $-\pi<x<\pi$, $\cos x = 0$ when $x =-\frac{\pi}{2}$ and $x=\frac{\pi}{2}$.

Answer:

$2$; $2$