watch the video and then solve the problem given below. click here to watch the video. determine the…

Explanation:

Step1: Recall amplitude formula

For $y = A\sin(Bx - C)+D$, amplitude is $|A|$. Here $A = 2$, so amplitude $=|2| = 2$.

Step2: Recall period formula

The period of $y=\sin(Bx)$ is $T=\frac{2\pi}{|B|}$. Here $B=\frac{1}{4}$, so $T=\frac{2\pi}{\left|\frac{1}{4}\right|}=8\pi$.

Step3: Recall phase - shift formula

For $y = A\sin(Bx - C)+D$, phase - shift is $\frac{C}{B}$. Here $C = 0$, so phase - shift is $\frac{0}{\frac{1}{4}}=0$.

Answer:

Amplitude: 2; Period: $8\pi$; Phase - shift: 0