whats the horizontal asymptote of the function? f(x)=(3x + 2)/(x^2 - 1) y = 3 no horizontal asymptote y = 2…

Explanation:

Step1: Identify degrees of polynomials

The degree of the numerator $3x + 2$ is $n = 1$, and the degree of the denominator $x^{2}-1$ is $m=2$.

Step2: Apply horizontal - asymptote rule

When $n<m$, the horizontal asymptote of the rational function $y = \frac{f(x)}{g(x)}$ is $y = 0$. Here, since $1<2$, the horizontal asymptote of $f(x)=\frac{3x + 2}{x^{2}-1}$ is $y = 0$.

Answer:

$y = 0$