if (y = xsin x), then (\frac{dy}{dx}=) \n(a) (sin x+cos x) \n(b) (sin x + xcos x) \n(c) (sin x - xcos x)…

Explanation:

Step1: Apply product - rule

The product - rule states that if $y = u\cdot v$, then $\frac{dy}{dx}=u\frac{dv}{dx}+v\frac{du}{dx}$. Here, $u = x$ and $v=\sin x$.

Step2: Find derivatives of $u$ and $v$

The derivative of $u = x$ with respect to $x$ is $\frac{du}{dx}=1$. The derivative of $v=\sin x$ with respect to $x$ is $\frac{dv}{dx}=\cos x$.

Step3: Substitute into product - rule

$\frac{dy}{dx}=x\cdot\cos x+\sin x\cdot1=\sin x + x\cos x$.

Answer:

B. $\sin x + x\cos x$