if you are given the graph of $h(x)=\\log_{6}x$, how could you graph $m(x)=\\log_{6}(x+3)$?\ntranslate each…

if you are given the graph of $h(x)=\\log_{6}x$, how could you graph $m(x)=\\log_{6}(x+3)$?\ntranslate each point of the graph of $h(x)$ 3 units up.\ntranslate each point of the graph of $h(x)$ 3 units left.\ntranslate each point of the graph of $h(x)$ 3 units right.\ntranslate each point of the graph of $h(x)$ 3 units down.

if you are given the graph of $h(x)=\\log_{6}x$, how could you graph $m(x)=\\log_{6}(x+3)$?\ntranslate each point of the graph of $h(x)$ 3 units up.\ntranslate each point of the graph of $h(x)$ 3 units left.\ntranslate each point of the graph of $h(x)$ 3 units right.\ntranslate each point of the graph of $h(x)$ 3 units down.

Answer

Brief Explanations:

For a function transformation of the form $m(x) = h(x + a)$, where $a>0$, the graph of $h(x)$ is shifted horizontally to the left by $a$ units. Here, $m(x)=\log_6(x+3)$ is $h(x)=\log_6 x$ with $x$ replaced by $x+3$, so the shift is 3 units left.

Answer:

Translate each point of the graph of $h(x)$ 3 units left.