2. why do you think a removable discontinuity (hole) doesnt produce an asymptote on the graph of a…

2. why do you think a removable discontinuity (hole) doesnt produce an asymptote on the graph of a polynomial function, even though it is excluded from the domain of the function?

2. why do you think a removable discontinuity (hole) doesnt produce an asymptote on the graph of a polynomial function, even though it is excluded from the domain of the function?

Answer

Brief Explanations:

A removable discontinuity is a single - point gap. An asymptote represents a value the function approaches but never reaches over an extended interval. Since a hole is just a single excluded point and not a long - term behavior of approaching a value without bound, it doesn't create an asymptote.

Answer:

A removable discontinuity is a single - point exclusion and not indicative of the long - term behavior required for an asymptote.