there are 1.5×10^{23} atoms in 2.5 moles of zinc.\na true\nb false

Explanation:

Step1: Recall Avogadro's number

Avogadro's number $N_A = 6.022\times 10^{23}\text{ atoms/mol}$.

Step2: Calculate number of atoms

The number of atoms $N$ in $n$ moles is given by $N=n\times N_A$. For $n = 2.5$ moles, $N=2.5\times6.022\times 10^{23}=1.5055\times 10^{24}$ atoms.

Answer:

b. FALSE