10. cl2o + h2o → 2 hocl if 79 grams of cl2o (molar mass 86.9 g/mol) are reacted, how many grams of hocl…

Explanation:

Step1: Calculate moles of Cl₂O

$n_{Cl_2O}=\frac{m_{Cl_2O}}{M_{Cl_2O}}=\frac{79\ g}{86.9\ g/mol}\approx0.91\ mol$

Step2: Determine mole - ratio

From the balanced equation $Cl_2O + H_2O\rightarrow2HOCl$, the mole - ratio of $Cl_2O$ to $HOCl$ is 1:2. So, $n_{HOCl}=2\times n_{Cl_2O}$. $n_{HOCl}=2\times0.91\ mol = 1.82\ mol$

Step3: Calculate mass of HOCl

$m_{HOCl}=n_{HOCl}\times M_{HOCl}=1.82\ mol\times52.46\ g/mol\approx95.58\ g$

Answer:

95.58 g