10. a triangular prism has a base area (b) of 7.3cm² and a volume of 71.54 cm³. the height of the prism must…

10. a triangular prism has a base area (b) of 7.3cm² and a volume of 71.54 cm³. the height of the prism must be \n \n a. 3.65 cm b. 7.3 cm c. 9.8 cm d. 19.6 cm \n \n 11. ice has a density of 0.92 grams per cubic centimeter. what is the total volume of a block of ice that has a mass of 2300 g? \n \n a. 2.1 cubic centimeters b. 2.5 cubic centimeters \n c. 2116 cubic centimeters d. 2500 cubic centimeters

10. a triangular prism has a base area (b) of 7.3cm² and a volume of 71.54 cm³. the height of the prism must be \n \n a. 3.65 cm b. 7.3 cm c. 9.8 cm d. 19.6 cm \n \n 11. ice has a density of 0.92 grams per cubic centimeter. what is the total volume of a block of ice that has a mass of 2300 g? \n \n a. 2.1 cubic centimeters b. 2.5 cubic centimeters \n c. 2116 cubic centimeters d. 2500 cubic centimeters

Answer

Question 10

Explanation:

Step1: Recall volume formula

The volume formula for a prism is $V = Bh$, where $V$ is volume, $B$ is base - area and $h$ is height.

Step2: Solve for height

We know $V = 71.54\ cm^{3}$ and $B=7.3\ cm^{2}$. Rearranging the formula for $h$ gives $h=\frac{V}{B}$. Substituting the values: $h=\frac{71.54}{7.3}=9.8\ cm$.

Answer:

C. 9.8 cm

Question 11

Explanation:

Step1: Recall density formula

The density formula is $\rho=\frac{m}{V}$, where $\rho$ is density, $m$ is mass and $V$ is volume.

Step2: Solve for volume

We know $\rho = 0.92\ g/cm^{3}$ and $m = 2300\ g$. Rearranging the formula for $V$ gives $V=\frac{m}{\rho}$. Substituting the values: $V=\frac{2300}{0.92}=2500\ cm^{3}$.

Answer:

D. 2500 cubic centimeters