100 compounds of the weak base $nh_3$ with 100 molecules water will be in what form in solution?\n100…

100 compounds of the weak base $nh_3$ with 100 molecules water will be in what form in solution?\n100 $nh_4^+$ and 100 $oh^-$ ions in solution\naround 50 $nh_3$, around 50 $h_2o$, around 25 $nh_4^+$, and 25 $oh^-$ ions in solution\naround 95 $nh_3$, around 95 $h_2o$, around 5 $nh_4^+$, and 5 $oh^-$ ions in solution\naround 50 $nh_3$, around 50 $h_2o$, around 50 $nh_4^+$, and 50 $oh^-$ ions in solution

100 compounds of the weak base $nh_3$ with 100 molecules water will be in what form in solution?\n100 $nh_4^+$ and 100 $oh^-$ ions in solution\naround 50 $nh_3$, around 50 $h_2o$, around 25 $nh_4^+$, and 25 $oh^-$ ions in solution\naround 95 $nh_3$, around 95 $h_2o$, around 5 $nh_4^+$, and 5 $oh^-$ ions in solution\naround 50 $nh_3$, around 50 $h_2o$, around 50 $nh_4^+$, and 50 $oh^-$ ions in solution

Answer

Brief Explanations:

Ammonia ($NH_3$) is a weak base. In water, it undergoes partial - ionization. The equilibrium for the reaction of ammonia with water is $NH_3 + H_2O\rightleftharpoons NH_4^++OH^-$. Since it is a weak base, only a small fraction of ammonia molecules will ionize. Out of 100 ammonia molecules, only a few will form $NH_4^+$ and $OH^-$ ions, while the majority will remain as $NH_3$ and $H_2O$.

Answer:

Around 95 $NH_3$, around 95 $H_2O$, around 5 $NH_4^+$, and 5 $OH^-$ ions in solution