11. fill in the table below for compounds with polyatomic ions. name: agno₃, sc(no₃)₃, caso₄, li₂cr₂o₇…

11. fill in the table below for compounds with polyatomic ions. name: agno₃, sc(no₃)₃, caso₄, li₂cr₂o₇. formula: sodium chlorite, barium cyanide, aluminum permanganate, ammonium hydroxide

11. fill in the table below for compounds with polyatomic ions. name: agno₃, sc(no₃)₃, caso₄, li₂cr₂o₇. formula: sodium chlorite, barium cyanide, aluminum permanganate, ammonium hydroxide

Answer

Explanation:

Step1: Identify polyatomic ions

For $Li_2Cr_2O_7$, the polyatomic ion is $Cr_2O_7^{2 -}$ (dichromate), and the name is lithium dichromate. For $CaSO_4$, the polyatomic ion is $SO_4^{2 -}$ (sulfate), and the name is calcium sulfate. For $Sc(NO_3)_3$, the polyatomic ion is $NO_3^{-}$ (nitrate), and the name is scandium(III) nitrate. For $AgNO_3$, the polyatomic ion is $NO_3^{-}$ (nitrate), and the name is silver nitrate. For ammonium hydroxide, the formula is $NH_4OH$ with polyatomic ions $NH_4^{+}$ (ammonium) and $OH^{-}$ (hydroxide). For aluminum permanganate, the formula is $Al(MnO_4)_3$ with polyatomic ion $MnO_4^{-}$ (permanganate). For barium cyanide, the formula is $Ba(CN)_2$ with polyatomic ion $CN^{-}$ (cyanide). For sodium chlorite, the formula is $NaClO_2$ with polyatomic ion $ClO_2^{-}$ (chlorite).

Answer:

Name Formula
Lithium Dichromate $Li_2Cr_2O_7$
Calcium Sulfate $CaSO_4$
Scandium(III) Nitrate $Sc(NO_3)_3$
Silver Nitrate $AgNO_3$
Ammonium Hydroxide $NH_4OH$
Aluminum Permanganate $Al(MnO_4)_3$
Barium Cyanide $Ba(CN)_2$
Sodium Chlorite $NaClO_2$