12. explain how the models you developed show that when methane combines with oxygen to form carbon dioxide…

12. explain how the models you developed show that when methane combines with oxygen to form carbon dioxide and water, no atoms are left over from the reaction.

12. explain how the models you developed show that when methane combines with oxygen to form carbon dioxide and water, no atoms are left over from the reaction.

Answer

Brief Explanations:

In a chemical reaction, atoms are neither created nor destroyed. This is known as the law of conservation of mass. In the given reaction (CH_4 + 2O_2\rightarrow CO_2 + 2H_2O), we can count the number of each type of atom on both sides of the equation.

  • Carbon atoms: On the left - hand side, there is 1 carbon atom in (CH_4). On the right - hand side, there is 1 carbon atom in (CO_2).
  • Hydrogen atoms: On the left - hand side, there are (4) hydrogen atoms in (CH_4). On the right - hand side, in (2H_2O), the number of hydrogen atoms is (2\times2 = 4).
  • Oxygen atoms: On the left - hand side, there are (2\times2=4) oxygen atoms in (2O_2). On the right - hand side, in (CO_2) there are (2) oxygen atoms and in (2H_2O) there are (2\times1 = 2) oxygen atoms. The total number of oxygen atoms on the right - hand side is (2 + 2=4).

Since the number of carbon, hydrogen, and oxygen atoms is the same on both sides of the chemical equation, no atoms are left over from the reaction.

Answer:

In the reaction (CH_4 + 2O_2\rightarrow CO_2 + 2H_2O), the number of carbon atoms (1 on each side), hydrogen atoms (4 on each side), and oxygen atoms (4 on each side) is equal. According to the law of conservation of mass (atoms are conserved in a chemical reaction), no atoms are left over.