15. calculate a technician experimentally determined the boiling point of octane to be 124.1°c. the actual…

15. calculate a technician experimentally determined the boiling point of octane to be 124.1°c. the actual boiling point of octane is 125.7°c. calculate the error and the percent error.
Answer
Explanation:
Step1: Calculate the error
The error is calculated as the experimental value minus the actual value. Let the experimental value $E = 124.1^{\circ}C$ and the actual value $A=125.7^{\circ}C$. $Error=E - A=124.1 - 125.7=- 1.6^{\circ}C$
Step2: Calculate the percent - error
The percent - error formula is $\text{Percent Error}=\left|\frac{E - A}{A}\right|\times100%$. Substitute $E = 124.1^{\circ}C$ and $A = 125.7^{\circ}C$ into the formula: $\text{Percent Error}=\left|\frac{124.1 - 125.7}{125.7}\right|\times100%=\left|\frac{-1.6}{125.7}\right|\times100%$ $=\frac{1.6}{125.7}\times100%\approx1.27%$
Answer:
Error: $-1.6^{\circ}C$; Percent Error: approximately $1.27%$