5/9/2025\nchemistry\n1. if i have 12 l of a gas 1.4 atm and 373 k, how many moles of gas do i have?

Explanation:

Step1: Identify the ideal - gas law formula

The ideal - gas law is $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is the number of moles, $R$ is the ideal - gas constant ($R=0.0821\ \frac{L\cdot atm}{mol\cdot K}$), and $T$ is temperature. We need to solve for $n$.

Step2: Rearrange the formula for $n$

$n=\frac{PV}{RT}$

Step3: Substitute the given values

Given $P = 1.4\ atm$, $V = 12\ L$, $T = 373\ K$, and $R = 0.0821\ \frac{L\cdot atm}{mol\cdot K}$. $n=\frac{1.4\ atm\times12\ L}{0.0821\ \frac{L\cdot atm}{mol\cdot K}\times373\ K}$ $n=\frac{16.8\ L\cdot atm}{30.6233\ \frac{L\cdot atm}{mol}}$ $n\approx0.55\ mol$

Answer:

$0.55\ mol$