21. complete the following table (9 marks)\nwhen you write and draw out your answers, you dont need to make…

21. complete the following table (9 marks)\nwhen you write and draw out your answers, you dont need to make a table but make your answers easy for me to read and understand. if you need to upload 3 pictures, that is possible.\n| compound | lewis dot diagram | structural diagram | vsepr (shape) name |\n| ---- | ---- | ---- | ---- |\n| a) sbr₂ | | | |\n| b) c₂i₄ | | | |\n| c) fsin | | | |\nyour answer:\n\n22. use the following terms below\n1. polar\n2. non - polar\nusing the numbers above, label whether the molecules below are polar or non - polar\nsbr₂______(first blank)\nc₂i₄______(second blank)\nfsin______(third blank)\n(record your three - digit answer in the numerical response section below.)\nyour answer: □□□
Answer
Explanation:
Step1: Determine Lewis - Dot Diagrams
For $SBr_2$: Sulfur has 6 valence electrons and each bromine has 7 valence electrons. Sulfur is the central atom. The Lewis - dot diagram has sulfur with 2 bonding pairs (to the two bromines) and 2 lone pairs. For $C_2I_4$: Each carbon has 4 valence electrons and each iodine has 7 valence electrons. There is a double - bond between the two carbons and each carbon is bonded to 2 iodines. For $FSiN$: Silicon has 4 valence electrons, fluorine has 7, nitrogen has 5. The possible Lewis - dot structure has silicon as the central atom with appropriate bonding to satisfy the octet rule.
Step2: Draw Structural Diagrams
For $SBr_2$, it has a bent structure around the sulfur atom. For $C_2I_4$, it has a planar structure with the double - bond between the carbons and iodines attached to the carbons. For $FSiN$, it has a linear or trigonal - planar like structure depending on the bonding arrangement.
Step3: Determine VSEPR Shapes
For $SBr_2$, with 2 bonding pairs and 2 lone pairs on the central sulfur atom, the VSEPR shape is bent. For $C_2I_4$, with double - bond and single bonds around carbon and no lone pairs on the central atoms (carbons), the shape around each carbon is trigonal - planar and overall planar. For $FSiN$, if silicon is the central atom with appropriate bonding, it can be linear or trigonal - planar.
Step4: Determine Polarity
For $SBr_2$, due to the bent shape and electronegativity difference between sulfur and bromine, it is polar. For $C_2I_4$, the molecule is symmetric, so it is non - polar. For $FSiN$, due to the electronegativity difference between the atoms and the possible non - symmetric structure, it is polar.
Answer:
| Compound | Lewis Dot Diagram | Structural Diagram | VSEPR (shape) name |
|---|---|---|---|
| $SBr_2$ | Sulfur with 2 bonding pairs to bromines and 2 lone pairs | Bent around sulfur | Bent |
| $C_2I_4$ | Double - bond between carbons and single bonds to iodines | Planar | Trigonal - planar around each carbon, planar overall |
| $FSiN$ | Silicon as central atom with appropriate bonding | Linear or trigonal - planar | Linear or trigonal - planar |
| For polarity: | |||
| $SBr_2$: 1 | |||
| $C_2I_4$: 2 | |||
| $FSiN$: 1 |