if 22.99 g of sodium and 35.45 g of chlorine fully react, how much sodium chloride forms?
if 22.99 g of sodium and 35.45 g of chlorine fully react, how much sodium chloride forms?
Answer
Explanation:
Step1: Apply law of conservation of mass
According to the law of conservation of mass, in a chemical reaction, the total mass of reactants equals the total mass of products.
Step2: Calculate mass of product
The mass of sodium is 22.99 g and the mass of chlorine is 35.45 g. The mass of sodium chloride formed is the sum of the masses of sodium and chlorine. $m_{NaCl}=22.99 + 35.45$ $m_{NaCl}=58.44$ g
Answer:
58.44 g