24. a student measured the volume of a liquid to be 215.5 ml. the correct value of the volume is 205.5 ml…

24. a student measured the volume of a liquid to be 215.5 ml. the correct value of the volume is 205.5 ml. what is the student’s percent error?\n% error = \\(\\frac{v_e - v_a}{v_a}\\times100\\)\n% error = \\(\\frac{\\text{ml}-\\text{ml}}{\\text{ml}}\\times100\\)\n% error = \n25. a student calculated the density of aluminum to be 2.95 g/cm³. the actual density of aluminum is 2.70 g/cm³. what is the student’s percent error?\n% error = \\(\\frac{v_e - v_a}{v_a}\\times100\\)\n% error = \\(\\frac{\\text{g/cm³}-\\text{g/cm³}}{\\text{g/cm³}}\\times100\\)\n% error =

24. a student measured the volume of a liquid to be 215.5 ml. the correct value of the volume is 205.5 ml. what is the student’s percent error?\n% error = \\(\\frac{v_e - v_a}{v_a}\\times100\\)\n% error = \\(\\frac{\\text{ml}-\\text{ml}}{\\text{ml}}\\times100\\)\n% error = \n25. a student calculated the density of aluminum to be 2.95 g/cm³. the actual density of aluminum is 2.70 g/cm³. what is the student’s percent error?\n% error = \\(\\frac{v_e - v_a}{v_a}\\times100\\)\n% error = \\(\\frac{\\text{g/cm³}-\\text{g/cm³}}{\\text{g/cm³}}\\times100\\)\n% error =

Answer

Explanation:

Step1: Identify values for problem 24

$V_E = 215.5$ mL, $V_A=205.5$ mL

Step2: Substitute values into percent - error formula

$% error=\frac{215.5 - 205.5}{205.5}\times100=\frac{10}{205.5}\times100$

Step3: Calculate the result

$% error\approx4.87%$

Step4: Identify values for problem 25

$V_E = 2.95$ g/cm³, $V_A = 2.70$ g/cm³

Step5: Substitute values into percent - error formula

$% error=\frac{2.95 - 2.70}{2.70}\times100=\frac{0.25}{2.70}\times100$

Step6: Calculate the result

$% error\approx9.26%$

Answer:

  1. Approximately $4.87%$
  2. Approximately $9.26%$