a 26.24 g gas sample occupies 4.48 l at stp. what is the molecular weight (molar mass) of this gas?\nstp =…

a 26.24 g gas sample occupies 4.48 l at stp. what is the molecular weight (molar mass) of this gas?\nstp = 273 k and 1.00 atm\nmolar mass = ? g/mol\ndo not round until the end.

a 26.24 g gas sample occupies 4.48 l at stp. what is the molecular weight (molar mass) of this gas?\nstp = 273 k and 1.00 atm\nmolar mass = ? g/mol\ndo not round until the end.

Answer

Explanation:

Step1: Find moles at STP

At STP, 1 mole of gas occupies 22.4 L. $n = \frac{V}{V_m} = \frac{4.48\ \text{L}}{22.4\ \text{L/mol}} = 0.2\ \text{mol}$

Step2: Calculate molar mass

Molar mass = mass / moles. $M = \frac{m}{n} = \frac{26.24\ \text{g}}{0.2\ \text{mol}}$

Answer:

131.2 g/mol