2al + 6hcl → 3h₂ + 2alcl₃\n2.6 mol alcl₃ form during the reaction.\nthe molar mass of alcl₃ is 133…

2al + 6hcl → 3h₂ + 2alcl₃\n2.6 mol alcl₃ form during the reaction.\nthe molar mass of alcl₃ is 133 g/mol.\nstep 2: what mass of alcl₃ forms?\n2.6 mol alcl₃ → ? g alcl₃

2al + 6hcl → 3h₂ + 2alcl₃\n2.6 mol alcl₃ form during the reaction.\nthe molar mass of alcl₃ is 133 g/mol.\nstep 2: what mass of alcl₃ forms?\n2.6 mol alcl₃ → ? g alcl₃

Answer

Explanation:

Step1: Recall mass - mole relationship formula

The formula to calculate mass ($m$) from moles ($n$) and molar mass ($M$) is $m = n\times M$.

Step2: Substitute given values

We are given $n = 2.6\ mol$ (number of moles of $AlCl_3$) and $M=133\ g/mol$ (molar mass of $AlCl_3$). So, $m=2.6\ mol\times133\ g/mol$.

Step3: Calculate the mass

$m = 2.6\times133=345.8\ g$.

Answer:

$345.8$