2c₂h₂(g) + 5o₂(g) → 4co₂(g) + 2h₂o(g)\nhow many liters of c₂h₂ are required to produce 8 l of co₂, assuming…

2c₂h₂(g) + 5o₂(g) → 4co₂(g) + 2h₂o(g)\nhow many liters of c₂h₂ are required to produce 8 l of co₂, assuming the reaction is at stp?\nthe ratios are: $\frac{2 l c₂h₂}{4 l co₂}$ or $\frac{4 l co₂}{2 l c₂h₂}$\n? l c₂h₂

2c₂h₂(g) + 5o₂(g) → 4co₂(g) + 2h₂o(g)\nhow many liters of c₂h₂ are required to produce 8 l of co₂, assuming the reaction is at stp?\nthe ratios are: $\frac{2 l c₂h₂}{4 l co₂}$ or $\frac{4 l co₂}{2 l c₂h₂}$\n? l c₂h₂

Answer

Explanation:

Step1: Set up the proportion

We know the ratio of $C_2H_2$ to $CO_2$ is $\frac{2\ L\ C_2H_2}{4\ L\ CO_2}$. Let $x$ be the volume of $C_2H_2$ needed to produce 8 L of $CO_2$. So we set up the proportion $\frac{x}{8\ L\ CO_2}=\frac{2\ L\ C_2H_2}{4\ L\ CO_2}$.

Step2: Solve for $x$

Cross - multiply: $4x = 2\times8$. Then $4x=16$. Divide both sides by 4: $x=\frac{16}{4}$.

Answer:

4 L $C_2H_2$