2c₂h₂(g) + 5o₂(g) → 4co₂(g) + 2h₂o(g)\nhow many liters of c₂h₂ are required to produce 8 l of co₂, assuming…

2c₂h₂(g) + 5o₂(g) → 4co₂(g) + 2h₂o(g)\nhow many liters of c₂h₂ are required to produce 8 l of co₂, assuming the reaction is at stp?\nthe ratios are: $\frac{2\text{ l }c_{2}h_{2}}{4\text{ l }co_{2}}$ or $\frac{4\text{ l }co_{2}}{2\text{ l }c_{2}h_{2}}$\n? l c₂h₂

2c₂h₂(g) + 5o₂(g) → 4co₂(g) + 2h₂o(g)\nhow many liters of c₂h₂ are required to produce 8 l of co₂, assuming the reaction is at stp?\nthe ratios are: $\frac{2\text{ l }c_{2}h_{2}}{4\text{ l }co_{2}}$ or $\frac{4\text{ l }co_{2}}{2\text{ l }c_{2}h_{2}}$\n? l c₂h₂

Answer

Explanation:

Step1: Set up proportion

Let $x$ be the volume of $C_2H_2$. We use the ratio $\frac{2\ L\ C_2H_2}{4\ L\ CO_2}=\frac{x}{8\ L\ CO_2}$.

Step2: Cross - multiply and solve for $x$

$4x = 2\times8$. Then $x=\frac{2\times8}{4}$.

Answer:

$4$