2co(g) + o₂(g) → 2co₂(g)\nif 6.0 l of co react at stp, how many liters of oxygen are required for the…

Explanation:

Step1: Determine mole - volume ratio

At STP, the volume ratio of gases is equal to the mole ratio in the balanced chemical equation. The balanced equation is $2CO(g)+O_2(g)\to2CO_2(g)$. The mole ratio of $CO$ to $O_2$ is $2:1$, so the volume ratio of $CO$ to $O_2$ is also $2:1$.

Step2: Calculate volume of $O_2$

Let $V_{O_2}$ be the volume of $O_2$. We know that $\frac{V_{CO}}{V_{O_2}}=\frac{2}{1}$. Given $V_{CO} = 6.0\ L$. Then $V_{O_2}=\frac{V_{CO}}{2}$. Substitute $V_{CO}=6.0\ L$ into the formula: $V_{O_2}=\frac{6.0\ L}{2}=3.0\ L$.

Answer:

$3.0$