c + 2f₂ → cf₄\nhow many grams of carbon tetrafluoride, cf₄, are produced from the complete reaction of 4.0…

c + 2f₂ → cf₄\nhow many grams of carbon tetrafluoride, cf₄, are produced from the complete reaction of 4.0 moles of fluorine, f₂?\nmolar mass cf₄: 88.01 g/mol\n? g cf₄
Answer
Explanation:
Step1: Determine the mole ratio
From the balanced equation (C + 2F_{2}\to CF_{4}), the mole ratio of (F_{2}) to (CF_{4}) is (2:1).
Step2: Calculate moles of (CF_{4})
Given (n(F_{2}) = 4.0\space mol). Using the mole ratio (\frac{n(CF_{4})}{n(F_{2})}=\frac{1}{2}), then (n(CF_{4})=\frac{1}{2}\times n(F_{2})). Substituting the value of (n(F_{2})), we get (n(CF_{4})=\frac{1}{2}\times4.0\space mol = 2.0\space mol).
Step3: Calculate mass of (CF_{4})
Using the formula (m = n\times M), where (M(CF_{4})=88.01\space g/mol) and (n(CF_{4}) = 2.0\space mol). Then (m(CF_{4})=n(CF_{4})\times M(CF_{4})=2.0\space mol\times88.01\space g/mol) (m(CF_{4}) = 176.02\space g)
Answer:
(176.02\space g)