c + 2f₂ → cf₄\nhow many grams of carbon tetrafluoride, cf₄, are produced from the complete reaction of 4.0…

c + 2f₂ → cf₄\nhow many grams of carbon tetrafluoride, cf₄, are produced from the complete reaction of 4.0 moles of fluorine, f₂?\nmolar mass cf₄: 88.01 g/mol\n? g cf₄

c + 2f₂ → cf₄\nhow many grams of carbon tetrafluoride, cf₄, are produced from the complete reaction of 4.0 moles of fluorine, f₂?\nmolar mass cf₄: 88.01 g/mol\n? g cf₄

Answer

Explanation:

Step1: Determine the mole ratio

From the balanced equation (C + 2F_{2}\to CF_{4}), the mole ratio of (F_{2}) to (CF_{4}) is (2:1).

Step2: Calculate moles of (CF_{4})

Given (n(F_{2}) = 4.0\space mol). Using the mole ratio (\frac{n(CF_{4})}{n(F_{2})}=\frac{1}{2}), then (n(CF_{4})=\frac{1}{2}\times n(F_{2})). Substituting the value of (n(F_{2})), we get (n(CF_{4})=\frac{1}{2}\times4.0\space mol = 2.0\space mol).

Step3: Calculate mass of (CF_{4})

Using the formula (m = n\times M), where (M(CF_{4})=88.01\space g/mol) and (n(CF_{4}) = 2.0\space mol). Then (m(CF_{4})=n(CF_{4})\times M(CF_{4})=2.0\space mol\times88.01\space g/mol) (m(CF_{4}) = 176.02\space g)

Answer:

(176.02\space g)