2h₂o ⇌ h₃o⁺ + oh⁻\nchoose the conjugate acid - base pairs from the above equation.\nselect all that apply\na…

2h₂o ⇌ h₃o⁺ + oh⁻\nchoose the conjugate acid - base pairs from the above equation.\nselect all that apply\na h₂o/h₃o⁺\nb h₂o/ha\nc oh⁻/h₂o\nd a⁻/h₃o⁺

2h₂o ⇌ h₃o⁺ + oh⁻\nchoose the conjugate acid - base pairs from the above equation.\nselect all that apply\na h₂o/h₃o⁺\nb h₂o/ha\nc oh⁻/h₂o\nd a⁻/h₃o⁺

Answer

Answer:

A. $H_2O/H_3O^{+}$, C. $OH^{-}/H_2O$

Explanation:

Step1: Define conjugate acid - base pair

A conjugate acid - base pair differs by one $H^{+}$.

Step2: Analyze $H_2O/H_3O^{+}$ pair

$H_2O$ gains a $H^{+}$ to form $H_3O^{+}$, so it's a conjugate acid - base pair.

Step3: Analyze $OH^{-}/H_2O$ pair

$OH^{-}$ gains a $H^{+}$ to form $H_2O$, so it's a conjugate acid - base pair.

Step4: Analyze $H_2O/HA$ pair

There is no $HA$ in the given equation, not a pair.

Step5: Analyze $A^{-}/H_3O^{+}$ pair

There is no $A^{-}$ in the given equation, not a pair.