9) 2kclo₃ → 2kcl + 6o₂\natom reactants products\nk\ncl\no

Explanation:

Step1: Count K atoms in reactants

There are 2 K atoms in (2KClO_3) as the coefficient of (KClO_3) is 2 and there is 1 K per (KClO_3) unit. So, reactants: 2.

Step2: Count K atoms in products

There are 2 K atoms in (2KCl) as the coefficient of (KCl) is 2 and there is 1 K per (KCl) unit. So, products: 2.

Step3: Count Cl atoms in reactants

There are 2 Cl atoms in (2KClO_3) as the coefficient of (KClO_3) is 2 and there is 1 Cl per (KClO_3) unit. So, reactants: 2.

Step4: Count Cl atoms in products

There are 2 Cl atoms in (2KCl) as the coefficient of (KCl) is 2 and there is 1 Cl per (KCl) unit. So, products: 2.

Step5: Count O atoms in reactants

There are 6 O atoms in (2KClO_3) as the coefficient of (KClO_3) is 2 and there are 3 O per (KClO_3) unit ((2\times3 = 6)). So, reactants: 6.

Step6: Count O atoms in products

There are 12 O atoms in (6O_2) as the coefficient of (O_2) is 6 and there are 2 O per (O_2) unit ((6\times2=12)). So, products: 12.

Atom	Reactants	Products
K	2	2
Cl	2	2
O	6	12

Answer:

Atom	Reactants	Products
K	2	2
Cl	2	2
O	6	12