2naoh + h₂so₄ → 2h₂o + na₂so₄\n50.0 ml of 0.50 m h₂so₄ is added to\n60.0 ml of 0.80 m naoh. the…

2naoh + h₂so₄ → 2h₂o + na₂so₄\n50.0 ml of 0.50 m h₂so₄ is added to\n60.0 ml of 0.80 m naoh. the resulting\ntemperature change is an increase of\n1.20 °c.\n\nc_sol = 4.20 j/g °c d_sol = 1.05 g/ml c_cal = 4.50 j/°c\n\nwhat is the mass of the solution?\nmass_sol = ? g

2naoh + h₂so₄ → 2h₂o + na₂so₄\n50.0 ml of 0.50 m h₂so₄ is added to\n60.0 ml of 0.80 m naoh. the resulting\ntemperature change is an increase of\n1.20 °c.\n\nc_sol = 4.20 j/g °c d_sol = 1.05 g/ml c_cal = 4.50 j/°c\n\nwhat is the mass of the solution?\nmass_sol = ? g

Answer

Explanation:

Step1: Calculate total volume of solution

The volume of (H_2SO_4) is (50.0\space mL) and the volume of (NaOH) is (60.0\space mL). So total volume (V = 50.0 + 60.0 = 110.0\space mL).

Step2: Calculate mass of solution using density

Density (d = 1.05\space g/mL) and volume (V = 110.0\space mL). Using the formula (mass = density\times volume), we get (mass = 1.05\times110.0). (mass = 115.5\space g)

Answer:

(115.5)