$2pocl_3(g) + heat leftrightarrow 2pcl_3(g) + o_2(g)$\nfor the equilibrium system described by this…

$2pocl_3(g) + heat leftrightarrow 2pcl_3(g) + o_2(g)$\nfor the equilibrium system described by this equation, what happens if the temperature is decreased?\nthe equilibrium will shift right.\nthe equilibrium will shift left.\nthe equilibrium will not change.

$2pocl_3(g) + heat leftrightarrow 2pcl_3(g) + o_2(g)$\nfor the equilibrium system described by this equation, what happens if the temperature is decreased?\nthe equilibrium will shift right.\nthe equilibrium will shift left.\nthe equilibrium will not change.

Answer

Brief Explanations:

The given reaction has heat as a reactant, so it is an endothermic process. According to Le Chatelier's principle, decreasing the temperature (removing heat, a reactant) will shift the equilibrium to favor the reverse reaction, which produces heat. This means the equilibrium shifts left to replenish the lost heat.

Answer:

The equilibrium will shift left.