4/30/2025\nchemistry\n1. if i have 2.5 l of a gas at 273 k and 100 kpa and i compress it to 1.4 l at 293 k…

Explanation:

Step1: Recall the combined - gas law

The combined - gas law is $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$, where $P_1$, $V_1$, $T_1$ are the initial pressure, volume and temperature respectively, and $P_2$, $V_2$, $T_2$ are the final pressure, volume and temperature respectively.

Step2: Identify the given values

$P_1 = 100\ kPa$, $V_1=2.5\ L$, $T_1 = 273\ K$, $V_2 = 1.4\ L$, $T_2=293\ K$.

Step3: Rearrange the combined - gas law to solve for $P_2$

$P_2=\frac{P_1V_1T_2}{V_2T_1}$.

Step4: Substitute the values into the formula

$P_2=\frac{100\ kPa\times2.5\ L\times293\ K}{1.4\ L\times273\ K}$. First, calculate the numerator: $100\times2.5\times293 = 73250$. Then, calculate the denominator: $1.4\times273=382.2$. Now, $P_2=\frac{73250}{382.2}\ kPa\approx192\ kPa$.

Answer:

$192\ kPa$