5. 352 ml of chlorine under a pressure of 680. mm hg are placed in a container under a pressure of 1210 mm…

5. 352 ml of chlorine under a pressure of 680. mm hg are placed in a container under a pressure of 1210 mm hg. the temperature remains constant at 296 k. what is the volume of the container in liters?

5. 352 ml of chlorine under a pressure of 680. mm hg are placed in a container under a pressure of 1210 mm hg. the temperature remains constant at 296 k. what is the volume of the container in liters?

Answer

Explanation:

Step1: Identify the gas - law formula

Since temperature is constant, we use Boyle's law $P_1V_1 = P_2V_2$.

Step2: Convert the initial volume to liters

$V_1=352\ mL = 352\times10^{- 3}\ L=0.352\ L$.

Step3: Rearrange Boyle's law to solve for $V_2$

$V_2=\frac{P_1V_1}{P_2}$.

Step4: Substitute the given values

$P_1 = 680\ mmHg$, $V_1=0.352\ L$, $P_2 = 210\ mmHg$. $V_2=\frac{680\ mmHg\times0.352\ L}{210\ mmHg}$.

Step5: Calculate the value of $V_2$

$V_2=\frac{680\times0.352}{210}\ L\approx1.14\ L$.

Answer:

$1.14\ L$