45. when the following solutions are mixed together, what precipitate (if any) will form?\na. feso₄(aq) +…

Explanation:

Step1: Analyze reaction (FeSO_{4}(aq)+KCl(aq))

Write the potential products by swapping ions: (FeCl_{2}) and (K_{2}SO_{4}). According to solubility rules, all chlorides (except (AgCl), (PbCl_{2}), (Hg_{2}Cl_{2})) are soluble and all sulfates (except (BaSO_{4}), (PbSO_{4}), (CaSO_{4}) (slightly soluble), (SrSO_{4})) are soluble. So no precipitate forms.

Step2: Analyze reaction (Al(NO_{3}){3}(aq)+Ba(OH){2}(aq))

Swap ions to get (Al(OH){3}) and (Ba(NO{3}){2}). By solubility rules, hydroxides of (Al^{3 +}) are insoluble ((Al(OH){3}) is a precipitate), while (Ba(NO_{3})_{2}) is soluble (all nitrates are soluble).

Step3: Analyze reaction (CaCl_{2}(aq)+Na_{2}SO_{4}(aq))

Swap ions: (CaSO_{4}) and (NaCl). (NaCl) is soluble (all sodium salts and chlorides (except some mentioned above) are soluble). (CaSO_{4}) is slightly soluble ((CaSO_{4}) can be considered as a precipitate in this context as per common precipitation reaction problems).

Step4: Analyze reaction (K_{2}S(aq)+Ni(NO_{3})_{2}(aq))

Swap ions: (NiS) and (KNO_{3}). (KNO_{3}) is soluble (all nitrates and potassium salts are soluble). Sulfides of transition - metal ions ((Ni^{2+})) are insoluble ((NiS) is a precipitate).

Answer:

a. No precipitate. b. (Al(OH){3}) precipitate. c. (CaSO{4}) precipitate. d. (NiS) precipitate.